# Leetcode 2022 - Convert 1D Array Into 2D Array

`Note:`

- Know how to convert
`2D`

index into`1D`

:`[i, j] => i * n + j`

. (i*n give us total grids before the curr row then we add j to that).`i * n + j => [floor(i/n), i %n]`

.

`Question:`

You are given a 0-indexed 1-dimensional (`1D`

) integer array `original`

, and two integers, m and n. You are tasked with creating a 2-dimensional (`2D`

) array with m rows and n columns using all the elements from `original`

.

The elements from indices `0`

to `n - 1`

(inclusive) of `original`

should form the first row of the constructed 2D array, the elements from indices n to `2 * n - 1`

(inclusive) should form the second row of the constructed 2D array, and so on.

Return an `m x n`

2D array constructed according to the above procedure, or an empty 2D array if it is impossible.

`Example:`

1 | Input: original = [1,2,3,4], m = 2, n = 2 |

`Code:`

1 | /** |